MCQOPTIONS
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| 1. |
Solubility product of silver bromide is \[5.0\times {{10}^{-13}}\]. The quantity of potassium bromid (molar mass taken as 120 g \[mo{{l}^{-1}}\]) to be added to 1 L of 0.05 M solution of silver nitrate to start the precipitatin of AgBr is |
| A. | \[1.2\times {{10}^{-10}}g\] |
| B. | \[1.2\times {{10}^{-9}}g\] |
| C. | \[6.2\times {{10}^{-5}}g\] |
| D. | \[5.0\times {{10}^{-8}}g\] |
| Answer» C. \[6.2\times {{10}^{-5}}g\] | |