\[{{\sin }^{-1}}\frac{\sqrt{x}}{\sqrt{x+a}}\]is equal to

1.	\[{{\sin }^{-1}}\frac{\sqrt{x}}{\sqrt{x+a}}\]is equal to
A.	\[{{\cos }^{-1}}\sqrt{\frac{x}{a}}\]
B.	\[\text{cose}{{\text{c}}^{-1}}\sqrt{\frac{x}{a}}\]
C.	\[{{\tan }^{-1}}\sqrt{\frac{x}{a}}\]
D.	None of these
Answer» D. None of these

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\[{{\sin }^{-1}}\frac{\sqrt{x}}{\sqrt{x+a}}\]is equal to

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