\[{{\sin }^{-1}}\frac{4}{5}+2{{\tan }^{-1}}\frac{1}{3}=\] [ISM Dhanbad 1971]

\[{{\sin }^{-1}}\frac{4}{5}+2{{\tan }^{-1}}\frac{1}{3}=\] [ISM Dhanb

1.	\[{{\sin }^{-1}}\frac{4}{5}+2{{\tan }^{-1}}\frac{1}{3}=\] [ISM Dhanbad 1971]
A.	\[\frac{\pi }{2}\]
B.	\[\frac{\pi }{3}\]
C.	\[\frac{\pi }{4}\]
D.	None of these
Answer» B. \[\frac{\pi }{3}\]

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\[{{\sin }^{-1}}\frac{4}{5}+2{{\tan }^{-1}}\frac{1}{3}=\] [ISM Dhanbad 1971]

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