1.

Simplify \[\frac{{{64}^{2x}}\div {{16}^{x}}}{{{128}^{x}}\times {{4}^{2x}}}\].

A.  \[{{2}^{-3x}}\]                   
B.         \[{{2}^{8x}}\]
C.  \[{{2}^{3x}}\]                   
D.         \[{{2}^{11x}}\]
Answer» B.         \[{{2}^{8x}}\]


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