Select the output for the following set of code : class sample { public int i; public int j; public void fun(int i, int j) { this.i = i; this.j = j; } } class Program { static void Main(string[] args) { sample s = new sample(); s.i = 1; s.j = 2; s.fun(s.i, s.j); Console.WriteLine(s.i + " " + s.j); Console.ReadLine(); } }

Question

Select the output for the following set of code :  class sample { public int i; public int j; public void fun(int i, int j) { this.i = i; this.j = j; } } class Program { static void Main(string[] args) { sample s = new sample(); s.i = 1; s.j = 2; s.fun(s.i, s.j); Console.WriteLine(s.i + " " + s.j); Console.ReadLine(); } }

TuteeHUB · Accepted Answer

Runs successfully but prints nothing

TuteeHUB · Answer

Error while calling s.fun() due to inaccessible level

TuteeHUB · Answer

Error as  this  reference would not be able to call  i  and  j

TuteeHUB · Answer

1 2

1.	Select the output for the following set of code : class sample { public int i; public int j; public void fun(int i, int j) { this.i = i; this.j = j; } } class Program { static void Main(string[] args) { sample s = new sample(); s.i = 1; s.j = 2; s.fun(s.i, s.j); Console.WriteLine(s.i + " " + s.j); Console.ReadLine(); } }
A.	Error while calling s.fun() due to inaccessible level
B.	Error as this reference would not be able to call i and j
C.	1 2
D.	Runs successfully but prints nothing
Answer» D. Runs successfully but prints nothing

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