1.

Select the code snippet which prints the element with maximum frequency.

A. public int findPopular(int[] a) { if (a == null || a.length ==
B. public int findPopular(int[] a) { if (a == null || a.length ==
C. public int findPopular(int[] a) { if (a == null || a.length ==
D. None of the mentioned
Answer» B. public int findPopular(int[] a) { if (a == null || a.length ==


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