\[(\sec A+\tan A-1)(\sec A-\tan A+1)-2\tan A=\][Roorkee 1972]

1.	\[(\sec A+\tan A-1)(\sec A-\tan A+1)-2\tan A=\][Roorkee 1972]
A.	\[\sec A\]
B.	\[2\sec A\]
C.	0
D.	1
Answer» D. 1

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\[(\sec A+\tan A-1)(\sec A-\tan A+1)-2\tan A=\][Roorkee 1972]

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