Resolved part of vector \[\vec{a}\] along vector \[\vec{b}\] is \[{{\vec{a}}_{1}}\] and that perpendicular to \[\vec{b}\] is \[{{\vec{a}}_{2}}\] then \[{{\vec{a}}_{1}}\times {{\vec{a}}_{2}}\] is equal to

\[\frac{(\vec{a}\cdot \vec{b})(\vec{b}\times \vec{a})}{\left| \vec{b}\times \vec{a} \right|}\]

\[\frac{(\vec{a}\times \vec{b})\cdot \vec{b}}{{{\left| {\vec{b}} \right|}^{2}}}\]

\[\frac{(\vec{a}\cdot \vec{b})\vec{a}}{{{\left| {\vec{a}} \right|}^{2}}}\]

\[\frac{(\vec{a}\cdot \vec{b})(\vec{b}\times \vec{a})}{{{\left| {\vec{b}} \right|}^{2}}}\]

Resolved part of vector \[\vec{a}\] along vector \[\vec{b}\] is \[{{\v

1.	Resolved part of vector \[\vec{a}\] along vector \[\vec{b}\] is \[{{\vec{a}}_{1}}\] and that perpendicular to \[\vec{b}\] is \[{{\vec{a}}_{2}}\] then \[{{\vec{a}}_{1}}\times {{\vec{a}}_{2}}\] is equal to
A.	\[\frac{(\vec{a}\times \vec{b})\cdot \vec{b}}{{{\left\| {\vec{b}} \right\|}^{2}}}\]
B.	\[\frac{(\vec{a}\cdot \vec{b})\vec{a}}{{{\left\| {\vec{a}} \right\|}^{2}}}\]
C.	\[\frac{(\vec{a}\cdot \vec{b})(\vec{b}\times \vec{a})}{{{\left\| {\vec{b}} \right\|}^{2}}}\]
D.	\[\frac{(\vec{a}\cdot \vec{b})(\vec{b}\times \vec{a})}{\left\| \vec{b}\times \vec{a} \right\|}\]
Answer» D. \[\frac{(\vec{a}\cdot \vec{b})(\vec{b}\times \vec{a})}{\left\| \vec{b}\times \vec{a} \right\|}\]

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Resolved part of vector \[\vec{a}\] along vector \[\vec{b}\] is \[{{\vec{a}}_{1}}\] and that perpendicular to \[\vec{b}\] is \[{{\vec{a}}_{2}}\] then \[{{\vec{a}}_{1}}\times {{\vec{a}}_{2}}\] is equal to

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