Reaction \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOBr}\] gives [CPMT 198

1.	Reaction \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOBr}\] gives [CPMT 1983, 93, 97]
A.	\[C{{H}_{3}}Br\]
B.	\[C{{H}_{4}}\]
C.	\[C{{H}_{3}}COBr\]
D.	\[C{{H}_{3}}N{{H}_{2}}\]
Answer» E.

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Reaction \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOBr}\] gives [CPMT 1983, 93, 97]

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