MCQOPTIONS
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| 1. |
Radiation of wavelength \[\lambda \], is incident on a photocell. The fastest emitted electron has speed v. If the wavelength is changed to \[\frac{3\lambda }{4}\], the speed of the fastest emitted electron will be: |
| A. | \[=v{{\left( \frac{4}{3} \right)}^{\frac{1}{2}}}\] |
| B. | \[=v{{\left( \frac{3}{4} \right)}^{\frac{1}{2}}}\] |
| C. | \[>v{{\left( \frac{4}{3} \right)}^{\frac{1}{2}}}\] |
| D. | \[<v{{\left( \frac{4}{3} \right)}^{\frac{1}{2}}}\] |
| Answer» D. \[<v{{\left( \frac{4}{3} \right)}^{\frac{1}{2}}}\] | |