MCQOPTIONS
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| 1. |
R is the radius of the earth and co is its angular velocity and \[{{\operatorname{g}}_{p}}\]is the value of g at the poles. The effective value of g at the latitude \[\lambda = 60{}^\circ \] will be equal to |
| A. | \[{{g}_{p}}-\frac{1}{4}R{{\omega }^{2}}\] |
| B. | \[{{g}_{p}}-\frac{3}{4}R{{\omega }^{2}}\] |
| C. | \[{{g}_{p}}-R{{\omega }^{2}}\] |
| D. | \[{{g}_{p}}+\frac{1}{4}R{{\omega }^{2}}\] |
| Answer» B. \[{{g}_{p}}-\frac{3}{4}R{{\omega }^{2}}\] | |