Quantity I : The average age of Mayank, Sachit, and Mudit is 32 years. The ratio of age of Mayank to Sachit is 4 : 3 and the age of Mudit is 16 years more than the age of Sachit. Find the age of Sachit. Quantity II : The age of A, B, C is (x + 4) years, (x + 8) years, and (x – 4) years respectively. The ratio of the age of A, 6 years before to the age of B, 2 years hence is 3 : 5. Find the average age of A, B and C.

Quantity I = Quantity II or relation can't be established

Quantity I : The average age of Mayank, Sachit, and Mudit is 32 years.

1.	Quantity I : The average age of Mayank, Sachit, and Mudit is 32 years. The ratio of age of Mayank to Sachit is 4 : 3 and the age of Mudit is 16 years more than the age of Sachit. Find the age of Sachit. Quantity II : The age of A, B, C is (x + 4) years, (x + 8) years, and (x – 4) years respectively. The ratio of the age of A, 6 years before to the age of B, 2 years hence is 3 : 5. Find the average age of A, B and C.
A.	Quantity : I > Quantity : II
B.	Quantity : I ≥ Quantity : II
C.	Quantity : I < Quantity : II
D.	Quantity : II ≥ Quantity : I
E.	Quantity I = Quantity II or relation can't be established
Answer» B. Quantity : I ≥ Quantity : II

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