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1. |
Q: PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles? |
A. | $$ {40{\sqrt{2}}}$$ |
B. | $$ {40{\sqrt{2}}}+ 40 $$ |
C. | $$ {40{\sqrt{2}}}+ 80 $$ |
D. | $$ {80{\sqrt{2}}}+ 80 $$ |
Answer» E. | |