1.

Q: PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?

A. $$ {40{\sqrt{2}}}$$
B. $$ {40{\sqrt{2}}}+ 40 $$
C. $$ {40{\sqrt{2}}}+ 80 $$
D. $$ {80{\sqrt{2}}}+ 80 $$
Answer» E.


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