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Q: In the figure given below, AD bisects ∠BAC. If the area of ΔABD=40 cm2 and AC=3AB, then the area of ΔABC: |
A. | $$ {150 \ cm^{2}}$$ |
B. | $$ {100 \ cm^{2}}$$ |
C. | $$ {120 \ cm^{2}}$$ |
D. | $$ {160 \ cm^{2}}$$ |
Answer» D. $$ {160 \ cm^{2}}$$ | |