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Q: If $$ {Acos^{2}θ+Bsin^{2}θ}={sin^{2}θ(sec^{2}θ+1)\over{sec^{2}θ-1}}$$ and cotθ=?

A. $${\sqrt{B-2\over2-A}}$$
B. $${\sqrt{B-1\over2-A}}$$
C. $${\sqrt{B-1\over A-2}}$$
D. $${\sqrt{2-B\over 2-A}}$$
Answer» C. $${\sqrt{B-1\over A-2}}$$


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