1.

Prussian blue is due to the formation of [BHU 1980; CBSE PMT 1990; KCET 1992; MP PET 1995]

A. \[F{{e}_{4}}{{\left[ Fe{{(CN)}_{6}} \right]}_{3}}\]
B. \[F{{e}_{2}}\left[ Fe{{(CN)}_{6}} \right]\]
C. \[F{{e}_{3}}\left[ Fe{{(CN)}_{6}} \right]\]
D. \[Fe{{\left[ Fe{{(CN)}_{6}} \right]}_{3}}\]
Answer» B. \[F{{e}_{2}}\left[ Fe{{(CN)}_{6}} \right]\]


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