Point out the error in the following program. #include #include int main() { char str1[] = "Learn through Compscibits 0.com", str2[120]; char *p; p = (char*) memccpy(str2, str1, 'i', strlen(str1)); *p = ' 0'; printf("%s", str2); return 0; }

Question

Point out the error in the following program.  #include #include int main() { char str1[] = "Learn through Compscibits 0.com", str2[120]; char *p; p = (char*) memccpy(str2, str1, 'i', strlen(str1)); *p = ' 0'; printf("%s", str2); return 0; }

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

Error: in memccpy statement

TuteeHUB · Answer

Error: invalid pointer conversion

TuteeHUB · Answer

Error: invalid variable declaration

TuteeHUB · Answer

No error and prints "Learn through Comp"

1.	Point out the error in the following program. #include #include int main() { char str1[] = "Learn through Compscibits 0.com", str2[120]; char p; p = (char) memccpy(str2, str1, 'i', strlen(str1)); *p = ' 0'; printf("%s", str2); return 0; }
A.	Error: in memccpy statement
B.	Error: invalid pointer conversion
C.	Error: invalid variable declaration
D.	No error and prints "Learn through Comp"
Answer» E.

Point out the error in the following program. #include #include int main() { char str1[] = "Learn through Compscibits 0.com", str2[120]; char p; p = (char) memccpy(str2, str1, 'i', strlen(str1)); *p = ' 0'; printf("%s", str2); return 0; }

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