Point out the error, if any in the for loop.
#include
int main()
{
int i=1;
for(;;)
{
printf("%d
", i++);
if(i10)
break;
}
return 0;
}

Question

Point out the error, if any in the for loop.
#include
int main()
{
    int i=1;
    for(;;)
    {
        printf("%d
", i++);
        if(i>10)
           break;
    }
    return 0;
}

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

There should be a condition in the for loop

TuteeHUB · Answer

The two semicolons should be dropped

TuteeHUB · Answer

The for loop should be replaced with while loop.

TuteeHUB · Answer

No error

1.	Point out the error, if any in the for loop. #include int main() { int i=1; for(;;) { printf("%d\n", i++); if(i>10) break; } return 0; }
A.	There should be a condition in the for loop
B.	The two semicolons should be dropped
C.	The for loop should be replaced with while loop.
D.	No error
Answer» E.

Point out the error, if any in the for loop. #include int main() { int i=1; for(;;) { printf("%d\n", i++); if(i>10) break; } return 0; }

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