1.

Periodic time of a satellite revolving above Earth?s surface at a height equal to R, radius of Earth, is [g is acceleration due to gravity at Earth?s surface]                                 [MP PMT 2002]

A.             \[2\pi \sqrt{\frac{2R}{g}}\]
B.               \[4\sqrt{2}\pi \sqrt{\frac{R}{g}}\]
C.             \[2\pi \sqrt{\frac{R}{g}}\]
D.               \[8\pi \sqrt{\frac{R}{g}}\]
Answer» C.             \[2\pi \sqrt{\frac{R}{g}}\]


Discussion

No Comment Found

Related MCQs