Operator overloading is

1.	Operator overloading is
A.	adding operation to the existing operators
B.	making the new operator
C.	making c++ operator works with objects
D.	giving new meaning to existing operator
E.	None of these
Answer» B. making the new operator

Discussion

No Comment Found

Related MCQs

What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; int main() { int p; p = 15 + 13 * 6; cout << p; return 0; } </iostream></pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; int main() { int p = 7, q = 9, r; r = (p > q) ? p : q; cout << r; return 0; } </iostream></pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; int main () { int p, q; p = 6; q = ++p * ++p; cout << p q = p++ * ++p; cout < return 0; } </iostream></pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class Example { public: int m, n; Example() {}; Example(int, int); Example operator + (Example); }; Example::Example (int p, int q) { m = p; n = q; } Example Example::operator+ (Example parameter) { Example container; container.m = m + parameter.m; container.n = n + parameter.n; return (container); } int main () { Example p (3,4); Example q (6,5); Example R; R = p + q; cout << R.m << "," << R.n; return 0; } </iostream></pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; void Add(int p, int q, int & r) { p = q + r; p = q + r; r = p + q; } int main() { int n = 6, m =4; Add(n, m, m); cout << n << " " << m; return 0; } </iostream></pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; ostream & operator< { return k; } int main() { cout << 10 << endl; cin.get(); return 0; } </iostream></pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> #include <string> using namespace std; class Example { public: operator string () { return "Converted..."; } }; int main() { Example examp; string str = examp; cout << str << endl; return 0; } </pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> #include <cmath> using namespace std; class ComplexNumber { private: double RealNumber; double ImagNumber; public: ComplexNumber(double r = 0.0, double i = 0.0) : RealNumber(r), ImagNumber(i) {} double mag() { return getMag(); } operator double () { return getMag(); } private: double getMag() { return sqrt(RealNumber * RealNumber + ImagNumber * ImagNumber); } }; int main() { ComplexNumber comp(2.0, 5.0); cout << comp.mag()< cout << comp; return 0; } </pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; class Example { public: Example(int k) : num_k(k) { } public: int operator()(int k = 0) const { return num_k + k; } operator int () const { return num_k; } private: int num_k; friend int g(const Example&); }; int fun(char Z) { return Z; } int main() { Example fun(6); cout << fun(5); return 0; } </pre>
What is the output of this program? <pre class="prettyprint lang-c">#include <iostream> using namespace std; main() { double num = 23.9399; float num0 = 20.23; int p ,q; p = (int) num; q = (int) num0; cout < } </iostream></pre>

Operator overloading is

Discussion

No Comment Found

Related MCQs

Reply to Comment