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1. |
Nitric acid can be produced from \[N{{H}_{3}}\] in three step process I. \[4N{{H}_{3}}(g)+5{{O}_{2}}(g)\xrightarrow{{}}4NO(g)+6{{H}_{2}}O(g)\] II. \[2NO(g)+{{O}_{2}}(g)\xrightarrow{{}}2N{{O}_{2}}(g)\] III. \[3N{{O}_{2}}(g)+{{H}_{2}}O(l)\xrightarrow{{}}2HN{{O}_{3}}(aq)+NO(g)\] % yield of Ist, IInd and IIIrd are respectively 40%, 50% and 70% respectively, then what volume of\[N{{H}_{3}}(g)\] sit 1 atm and \[0{}^\circ C\] required to produce 1075 g of \[HN{{O}_{3}}\]? |
A. | 3413 L |
B. | 3500 L |
C. | 6826 L |
D. | 1750 L |
Answer» B. 3500 L | |