1.

Natural glucose is termed D-glucose because:

A. \[-OH\] on the second carbon is on the right side in Fischer projection
B. \[-OH\] on the sixth carbon is on the right side in Fischer projection.
C. \[-OH\] on the fifth carbon is on the right side in Fischer projection.
D. It is dextrorotatory.
Answer» D. It is dextrorotatory.


Discussion

No Comment Found