

MCQOPTIONS
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1. |
Natural glucose is termed D-glucose because: |
A. | \[-OH\] on the second carbon is on the right side in Fischer projection |
B. | \[-OH\] on the sixth carbon is on the right side in Fischer projection. |
C. | \[-OH\] on the fifth carbon is on the right side in Fischer projection. |
D. | It is dextrorotatory. |
Answer» D. It is dextrorotatory. | |