MCQOPTIONS
Saved Bookmarks
| 1. |
Natural glucose is termed D-glucose because: |
| A. | \[-OH\] on the second carbon is on the right side in Fischer projection |
| B. | \[-OH\] on the sixth carbon is on the right side in Fischer projection. |
| C. | \[-OH\] on the fifth carbon is on the right side in Fischer projection. |
| D. | It is dextrorotatory. |
| Answer» D. It is dextrorotatory. | |