MCQOPTIONS
Saved Bookmarks
| 1. |
Moment of inertia of a magnetic needle is 40 gm-cm2 has time period 3 seconds in earth's horizontal field = \[3.6\times {{10}^{-5}}\]weber/m2. Its magnetic moment will be |
| A. | \[0.5\,A\times {{m}^{2}}\] |
| B. | \[5\,A\times {{m}^{2}}\] |
| C. | \[0.250\,A\times {{m}^{2}}\] |
| D. | \[5\times {{10}^{2}}A\times {{m}^{2}}\] |
| Answer» B. \[5\,A\times {{m}^{2}}\] | |