Match List I with List II.Let A and B be events with P(A) = \(\frac{2}{3}\), P(B) = \(\frac{1}{2}\) and P (A ∩ B) = \(\frac{1}{3}\)List- IList - IIProbability of an event Value(A) P (A ∩ Bc)(I) \(\frac{2}{3}\)(B) P (A ∪ Bc)(II) \(\frac{1}{3}\)(C) P (Ac ∩ Bc)(III) \(\frac{5}{6}\)(D) P (Ac ∪ Bc)(IV) \(\frac{1}{6}\)(Here c stands for complement)Choose the correct answer from the options given below:

• A. (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
• B. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
• C. (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
• D. (A)-(II), (B)-(IV), (C)-(III), (D)-(I)