Match List I with List II and select the correct answer using the code given below the lists:List IList IIOxidising agent(p) Disproportionation$$M{{n}_{3}}{{O}_{4}}$$(q) Redox reaction$${{C}_{6}}{{H}_{6}}$$(r) Decreases oxidation number$$2C{{u}^{+}}\xrightarrow{{}}C{{u}^{2+}}$$$$+C{{u}^{0}}$$(s) Fractional oxidation number(E) $${{H}_{2}}{{O}_{2}}+{{O}_{3}}\xrightarrow{{}}$$$${{H}_{2}}O+2{{O}_{2}}$$(t) Oxidation number is -1Codes:

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

A$$\to $$q, B$$\to $$p, C$$\to $$t, D$$\to $$s, E$$\to $$r

TuteeHUB · Answer

A$$\to $$t, B$$\to $$s, C$$\to $$r, D$$\to $$q, E$$\to $$P

TuteeHUB · Answer

A$$\to $$r, B$$\to $$t, C$$\to $$s, D$$\to $$p, E$$\to $$q

TuteeHUB · Answer

A$$\to $$r, B$$\to $$s, C$$\to $$t, D$$\to $$p, E$$\to $$q

1.	Match List I with List II and select the correct answer using the code given below the lists:List IList IIOxidising agent(p) Disproportionation\[M{{n}_{3}}{{O}_{4}}\](q) Redox reaction\[{{C}_{6}}{{H}_{6}}\](r) Decreases oxidation number\[2C{{u}^{+}}\xrightarrow{{}}C{{u}^{2+}}\]\[+C{{u}^{0}}\](s) Fractional oxidation number(E) \[{{H}_{2}}{{O}_{2}}+{{O}_{3}}\xrightarrow{{}}\]\[{{H}_{2}}O+2{{O}_{2}}\](t) Oxidation number is -1Codes:
A.	A\[\to \]q, B\[\to \]p, C\[\to \]t, D\[\to \]s, E\[\to \]r
B.	A\[\to \]t, B\[\to \]s, C\[\to \]r, D\[\to \]q, E\[\to \]P
C.	A\[\to \]r, B\[\to \]t, C\[\to \]s, D\[\to \]p, E\[\to \]q
D.	A\[\to \]r, B\[\to \]s, C\[\to \]t, D\[\to \]p, E\[\to \]q
Answer» E.

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