Magnetic field intensity (H), within a magnetic material where, M = 15

1.	Magnetic field intensity (H), within a magnetic material where, M = 150 A/m, μ = 1.5 × 10-5 H/m, μr = 30;
A.	14.921 A/m
B.	14.138 A/m
C.	1.82 A/m
D.	13.715 A/m
Answer» E.

Discussion

No Comment Found

Related MCQs

A coil of 500 turns wound on a core of non-magnetic material has an inductance of 20 mH. The average value of the EMF induced when a current of 2 A is reversed in 5 ms is:
Hysteresis loss in a transformer is proportional to which of the following quantity?
Magnetic field intensity has the dimension
A long straight wire carries a current I = 10 A. At what distance is the magnetic field H = 1 A/m?
Directions: The following items consist of two statements, one labeled as “Assertion(A)” and the other labeled as “Reason(R)”. You are to examine the two statements carefully and decide if the Assertion(A) and the Reason(R) are individually true and if so whether the reason is a correct explanation of the assertion. Select your answer to these items using the codes given below and mark your answer accordingly.Assertion (A): The magnetic flux per unit length through a loop of small length is called the magnetic flux density.Reason (R): The direction of magnetic flux density is taken as the normal to the plane of the loop when oriented to enclose maximum flux.
Magnetic field intensity (H) of a long conductor carrying current ‘I’ at a distance ‘r’ is _________
"In all cases electromagnetic induction, an induced voltage will cause a current to flow in a closed circuit in such a direction that the magnetic field which is caused by that current will oppose the change that produces the current", is the original statement of _____.
A conductor of length 100 cm moves at right angle to a uniform field flux density of 1.5 Wb/m2 with a velocity of 50 m/s. The e.m.f. induced in the conductor will be
A 25 μC point charge is located at origin. Calculate electric flux passing through the portion of sphere defined by r = 20 cm, bounded by θ = 0 and π rad, ϕ = 0 and π/2 rad.
A solenoid has 4000 turns over it with inductance of 0.126 H. The energy stored in the magnetic field, when a current of 2 A flows in the solenoid will be

Magnetic field intensity (H), within a magnetic material where, M = 150 A/m, μ = 1.5 × 10-5 H/m, μr = 30;

Discussion

No Comment Found

Related MCQs

Reply to Comment