\[{{\log }_{e}}(x+1)-{{\log }_{e}}(x-1)=\]

1.	\[{{\log }_{e}}(x+1)-{{\log }_{e}}(x-1)=\]
A.	\[2\,\left[ x+\frac{{{x}^{3}}}{3}+\frac{{{x}^{5}}}{5}+......\infty \right]\]
B.	\[\,\left[ x+\frac{{{x}^{3}}}{3}+\frac{{{x}^{5}}}{5}+......\infty \right]\]
C.	\[2\,\left[ \frac{1}{x}+\frac{1}{3{{x}^{3}}}+\frac{1}{5{{x}^{5}}}+...\infty \right]\]
D.	\[\,\left[ \frac{1}{x}+\frac{1}{3{{x}^{3}}}+\frac{1}{5{{x}^{5}}}+...\infty \right]\]
Answer» D. \[\,\left[ \frac{1}{x}+\frac{1}{3{{x}^{3}}}+\frac{1}{5{{x}^{5}}}+...\infty \right]\]

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\[{{\log }_{e}}(x+1)-{{\log }_{e}}(x-1)=\]

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