Line \[\vec{r}=\vec{a}+\lambda \vec{b}\] will not meet the plane \[\vec{r}\cdot \vec{n}=q\], if

\[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}=q\]

\[\vec{b}\cdot \vec{n}=0,\,\,\vec{a}\cdot \vec{n}=q\]

\[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}\ne q\]

\[\vec{b}\cdot \vec{n}=0,\,\,\vec{a}\cdot \vec{n}\ne q\]

Line \[\vec{r}=\vec{a}+\lambda \vec{b}\] will not meet the plane \[\ve

1.	Line \[\vec{r}=\vec{a}+\lambda \vec{b}\] will not meet the plane \[\vec{r}\cdot \vec{n}=q\], if
A.	\[\vec{b}\cdot \vec{n}=0,\,\,\vec{a}\cdot \vec{n}=q\]
B.	\[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}\ne q\]
C.	\[\vec{b}\cdot \vec{n}=0,\,\,\vec{a}\cdot \vec{n}\ne q\]
D.	\[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}=q\]
Answer» D. \[\vec{b}\cdot \vec{n}\ne 0,\,\,\vec{a}\cdot \vec{n}=q\]

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Line \[\vec{r}=\vec{a}+\lambda \vec{b}\] will not meet the plane \[\vec{r}\cdot \vec{n}=q\], if

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