Let \(X\left( s \right) = \frac{{3s + 5}}{{{s^2} + 10s + 21}}\) be the Laplace Transform of a signal x(t). Then x(0+) is

Let \(X\left( s \right) = \frac{{3s + 5}}{{{s^2} + 10s + 21}}\) be t

1.	Let \(X\left( s \right) = \frac{{3s + 5}}{{{s^2} + 10s + 21}}\) be the Laplace Transform of a signal x(t). Then x(0+) is
A.	0
B.	3
C.	5
D.	21
Answer» C. 5