Let \(X(s) = \frac{{3{s^2} + 5s}}{{{s^2} + 10s + 21}}\) be the Laplace Transform of a signal x(t). Then X(0+) is

Let \(X(s) = \frac{{3{s^2} + 5s}}{{{s^2} + 10s + 21}}\) be the Lapla

1.	Let \(X(s) = \frac{{3{s^2} + 5s}}{{{s^2} + 10s + 21}}\) be the Laplace Transform of a signal x(t). Then X(0+) is
A.	0
B.	3
C.	5
D.	21
Answer» B. 3