Let \[{{x}^{2}}+3{{y}^{2}}=3\] be the equation of an ellipse in the x-y plane. A and B are two points whose position vectors are \[-\sqrt{3}\hat{i}\] and\[-\sqrt{3}\hat{i}+2\hat{k}\]. Then the position vector of a point P on the ellipse such that \[\angle APB=\pi /4\] is

Let \[{{x}^{2}}+3{{y}^{2}}=3\] be the equation of an ellipse in the x-

1.	Let \[{{x}^{2}}+3{{y}^{2}}=3\] be the equation of an ellipse in the x-y plane. A and B are two points whose position vectors are \[-\sqrt{3}\hat{i}\] and\[-\sqrt{3}\hat{i}+2\hat{k}\]. Then the position vector of a point P on the ellipse such that \[\angle APB=\pi /4\] is
A.	\[\pm \hat{j}\]
B.	\[\pm (\hat{i}+\hat{j})\]
C.	\[\pm \,\hat{i}\]
D.	None of these
Answer» B. \[\pm (\hat{i}+\hat{j})\]

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Let \[{{x}^{2}}+3{{y}^{2}}=3\] be the equation of an ellipse in the x-y plane. A and B are two points whose position vectors are \[-\sqrt{3}\hat{i}\] and\[-\sqrt{3}\hat{i}+2\hat{k}\]. Then the position vector of a point P on the ellipse such that \[\angle APB=\pi /4\] is

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