Let \[{{x}_{1}}\] and \[{{y}_{1}}\] be real numbers. If \[{{z}_{1}}\] and \[{{z}_{2}}\] are complex numbers such that \[|{{z}_{1}}|=|{{z}_{2}}|=4,\] then \[|{{x}_{1}}{{z}_{1}}-{{y}_{1}}{{z}_{2}}{{|}^{2}}+|{{y}_{1}}{{z}_{1}}+{{x}_{1}}{{z}_{2}}{{|}^{2}}=\]

\[16({{x}_{1}}^{2}+{{y}_{1}}^{2})\]

\[32({{x}_{1}}^{2}+{{y}_{1}}^{2})\]

\[4({{x}_{1}}^{2}+{{y}_{1}}^{2})\]

\[32({{x}_{1}}^{2}+{{y}_{1}}^{2})|{{z}_{1}}+{{z}_{2}}{{|}^{2}}\]

Let \[{{x}_{1}}\] and \[{{y}_{1}}\] be real numbers. If \[{{z}_{1}}\]

1.	Let \[{{x}_{1}}\] and \[{{y}_{1}}\] be real numbers. If \[{{z}_{1}}\] and \[{{z}_{2}}\] are complex numbers such that \[\|{{z}_{1}}\|=\|{{z}_{2}}\|=4,\] then \[\|{{x}_{1}}{{z}_{1}}-{{y}_{1}}{{z}_{2}}{{\|}^{2}}+\|{{y}_{1}}{{z}_{1}}+{{x}_{1}}{{z}_{2}}{{\|}^{2}}=\]
A.	\[32({{x}_{1}}^{2}+{{y}_{1}}^{2})\]
B.	\[16({{x}_{1}}^{2}+{{y}_{1}}^{2})\]
C.	\[4({{x}_{1}}^{2}+{{y}_{1}}^{2})\]
D.	\[32({{x}_{1}}^{2}+{{y}_{1}}^{2})\|{{z}_{1}}+{{z}_{2}}{{\|}^{2}}\]
Answer» B. \[16({{x}_{1}}^{2}+{{y}_{1}}^{2})\]

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Let \[{{x}_{1}}\] and \[{{y}_{1}}\] be real numbers. If \[{{z}_{1}}\] and \[{{z}_{2}}\] are complex numbers such that \[|{{z}_{1}}|=|{{z}_{2}}|=4,\] then \[|{{x}_{1}}{{z}_{1}}-{{y}_{1}}{{z}_{2}}{{|}^{2}}+|{{y}_{1}}{{z}_{1}}+{{x}_{1}}{{z}_{2}}{{|}^{2}}=\]

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