Let $$[{{\varepsilon }_{0}}]$$ denotes the dimensional formula of the permittivity of the vacuum and $$[{{\mu }_{0}}]$$ that of the permeability of the vacuum. If $$M=\text{mass}$$, $$L=\text{length}$$, $$T=\text{Time}$$ and $$I=\text{electric current}$$, then [IIT 1998]

Question

Let $$[{{\varepsilon }_{0}}]$$ denotes the dimensional formula of the permittivity of the vacuum and $$[{{\mu }_{0}}]$$ that of the permeability of the vacuum. If $$M=\text{mass}$$, $$L=\text{length}$$, $$T=\text{Time}$$ and $$I=\text{electric current}$$, then                                 [IIT 1998]

TuteeHUB · Accepted Answer

$$[{{\mu }_{0}}]=ML{{T}^{-2}}{{I}^{-2}}$$

TuteeHUB · Answer

$$[{{\varepsilon }_{0}}]={{M}^{-1}}{{L}^{-3}}{{T}^{2}}I$$

TuteeHUB · Answer

$$[{{\varepsilon }_{0}}]={{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{I}^{2}}$$

TuteeHUB · Answer

$$[{{\mu }_{0}}]=M{{L}^{2}}{{T}^{-1}}I$$

1.	Let \[[{{\varepsilon }_{0}}]\] denotes the dimensional formula of the permittivity of the vacuum and \[[{{\mu }_{0}}]\] that of the permeability of the vacuum. If \[M=\text{mass}\], \[L=\text{length}\], \[T=\text{Time}\] and \[I=\text{electric current}\], then [IIT 1998]
A.	\[[{{\varepsilon }_{0}}]={{M}^{-1}}{{L}^{-3}}{{T}^{2}}I\]
B.	\[[{{\varepsilon }_{0}}]={{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{I}^{2}}\]
C.	\[[{{\mu }_{0}}]=ML{{T}^{-2}}{{I}^{-2}}\]
D.	\[[{{\mu }_{0}}]=M{{L}^{2}}{{T}^{-1}}I\]
Answer» C. \[[{{\mu }_{0}}]=ML{{T}^{-2}}{{I}^{-2}}\]

Let \[[{{\varepsilon }_{0}}]\] denotes the dimensional formula of the permittivity of the vacuum and \[[{{\mu }_{0}}]\] that of the permeability of the vacuum. If \[M=\text{mass}\], \[L=\text{length}\], \[T=\text{Time}\] and \[I=\text{electric current}\], then [IIT 1998]

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