Let the sequence \[\] of real numbers satisfies the recurrence relation \[{{b}_{n+1}}=\frac{1}{3}\left( 2{{b}_{n}}+\frac{125}{{{b}^{2}}_{n}} \right),{{b}_{n}}\ne 0.\] Then find \[\underset{n\,\to \,\infty }{\mathop{\lim }}\,{{b}_{n}}.\]

Let the sequence \[\] of real numbers satisfies the recurrence relatio

1.	Let the sequence \[\] of real numbers satisfies the recurrence relation \[{{b}_{n+1}}=\frac{1}{3}\left( 2{{b}_{n}}+\frac{125}{{{b}^{2}}_{n}} \right),{{b}_{n}}\ne 0.\] Then find \[\underset{n\,\to \,\infty }{\mathop{\lim }}\,{{b}_{n}}.\]
A.	10
B.	15
C.	5
D.	25
Answer» D. 25

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Let the sequence \[\] of real numbers satisfies the recurrence relation \[{{b}_{n+1}}=\frac{1}{3}\left( 2{{b}_{n}}+\frac{125}{{{b}^{2}}_{n}} \right),{{b}_{n}}\ne 0.\] Then find \[\underset{n\,\to \,\infty }{\mathop{\lim }}\,{{b}_{n}}.\]

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