Let the refractive index of a denser medium with respect to a rarer medium be $${{n}_{12}}$$ and its critical angle be $${{\theta }_{C}}$$. At an angle of incidence A when light is travelling from denser medium to rarer medium, a part of the light is reflected and the rest is refracted and the angle between reflected and refracted rays is $$90{}^\circ .$$Angle A is given by:

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$\frac{1}{{{\cos }^{-1}}\left( \sin {{\theta }_{C}} \right)}$$

TuteeHUB · Answer

$$\frac{1}{{{\tan }^{-1}}\left( \sin {{\theta }_{C}} \right)}$$

TuteeHUB · Answer

$${{\cos }^{-1}}\left( \sin {{\theta }_{C}} \right)$$

TuteeHUB · Answer

$${{\tan }^{-1}}\left( \sin {{\theta }_{C}} \right)$$

1.	Let the refractive index of a denser medium with respect to a rarer medium be \[{{n}_{12}}\] and its critical angle be \[{{\theta }_{C}}\]. At an angle of incidence A when light is travelling from denser medium to rarer medium, a part of the light is reflected and the rest is refracted and the angle between reflected and refracted rays is \[90{}^\circ .\]Angle A is given by:
A.	\[\frac{1}{{{\cos }^{-1}}\left( \sin {{\theta }_{C}} \right)}\]
B.	\[\frac{1}{{{\tan }^{-1}}\left( \sin {{\theta }_{C}} \right)}\]
C.	\[{{\cos }^{-1}}\left( \sin {{\theta }_{C}} \right)\]
D.	\[{{\tan }^{-1}}\left( \sin {{\theta }_{C}} \right)\]
Answer» E.

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