Let the function f be defined by \[f(x)=\frac{2x+1}{1-3x}\], then \[{{f}^{-1}}(x)\] is [Kerala (Engg.) 2002]

Let the function f be defined by \[f(x)=\frac{2x+1}{1-3x}\], then \[{{

1.	Let the function f be defined by \[f(x)=\frac{2x+1}{1-3x}\], then \[{{f}^{-1}}(x)\] is [Kerala (Engg.) 2002]
A.	\[\frac{x-1}{3x+2}\]
B.	\[\frac{3x+2}{x-1}\]
C.	\[\frac{x+1}{3x-2}\]
D.	\[\frac{2x+1}{1-3x}\]
Answer» B. \[\frac{3x+2}{x-1}\]

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Let the function f be defined by \[f(x)=\frac{2x+1}{1-3x}\], then \[{{f}^{-1}}(x)\] is [Kerala (Engg.) 2002]

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