Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then \[{{P}^{2}}{{R}^{3}}:{{S}^{3}}\] is equal to

\[{{\left( \text{first term} \right)}^{\text{2}}}\text{: }{{\left( \text{common ratio} \right)}^{\text{2}}}\]

\[{{\left( common\text{ }ratio \right)}^{n}}:1\]

Let S be the sum, P be the product and R be the sum of the reciprocals

1.	Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then \[{{P}^{2}}{{R}^{3}}:{{S}^{3}}\] is equal to
A.	0.0423611111111111
B.	Common ratio: 1
C.	\[{{\left( \text{first term} \right)}^{\text{2}}}\text{: }{{\left( \text{common ratio} \right)}^{\text{2}}}\]
D.	\[{{\left( common\text{ }ratio \right)}^{n}}:1\]
Answer» B. Common ratio: 1

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Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then \[{{P}^{2}}{{R}^{3}}:{{S}^{3}}\] is equal to

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