Let \[P=\{(x,y):\left| {{x}^{2}}+{{y}^{2}} \right|=1,x,y\in R\}.\] Then P is

Let \[P=\{(x,y):\left| {{x}^{2}}+{{y}^{2}} \right|=1,x,y\in R\}.\] The

1.	Let \[P=\{(x,y):\left\| {{x}^{2}}+{{y}^{2}} \right\|=1,x,y\in R\}.\] Then P is
A.	Reflexive
B.	Symmetric
C.	Transitive
D.	Anti-symmetric
Answer» C. Transitive

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Let \[P=\{(x,y):\left| {{x}^{2}}+{{y}^{2}} \right|=1,x,y\in R\}.\] Then P is

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