Let \[{{m}_{p}}\]be the mass of a proton, \[{{m}_{n}}\]that of a neutron, \[{{M}_{1}}\]that of a \[_{10}^{20}Ne\] nucleus and \[{{M}_{2}}\] that of a \[_{20}^{40}Ca\] nucleus. Then

\[{{M}_{1}}<10({{m}_{p}}+{{m}_{n}})\]

Let \[{{m}_{p}}\]be the mass of a proton, \[{{m}_{n}}\]that of a neutr

1.	Let \[{{m}_{p}}\]be the mass of a proton, \[{{m}_{n}}\]that of a neutron, \[{{M}_{1}}\]that of a \[_{10}^{20}Ne\] nucleus and \[{{M}_{2}}\] that of a \[_{20}^{40}Ca\] nucleus. Then
A.	\[{{M}_{2}}=2{{M}_{1}}\]
B.	\[{{M}_{1}}<10({{m}_{p}}+{{m}_{n}})\]
C.	\[{{M}_{2}}>2{{M}_{1}}\]
D.	\[{{M}_{1}}={{M}_{2}}\]
Answer» B. \[{{M}_{1}}<10({{m}_{p}}+{{m}_{n}})\]

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Let \[{{m}_{p}}\]be the mass of a proton, \[{{m}_{n}}\]that of a neutron, \[{{M}_{1}}\]that of a \[_{10}^{20}Ne\] nucleus and \[{{M}_{2}}\] that of a \[_{20}^{40}Ca\] nucleus. Then

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