Let \[\left| \,\begin{matrix} 6i & -3i & 1 \\ 4 & 3i & -1 \\ 20 & 3 & i \\ \end{matrix}\, \right|=x+iy\], then [IIT 1998]

Let \[\left| \,\begin{matrix} 6i & -3i & 1 \\ 4 & 3i & -1�

1.	Let \[\left\| \,\begin{matrix} 6i & -3i & 1 \\ 4 & 3i & -1 \\ 20 & 3 & i \\ \end{matrix}\, \right\|=x+iy\], then [IIT 1998]
A.	\[x=3,y=1\]
B.	\[x=0,y=0\]
C.	\[x=0,y=3\]
D.	\[x=1,y=3\]
Answer» C. \[x=0,y=3\]

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Let \[\left| \,\begin{matrix} 6i & -3i & 1 \\ 4 & 3i & -1 \\ 20 & 3 & i \\ \end{matrix}\, \right|=x+iy\], then [IIT 1998]

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