Let \[{{I}_{1}}=\int_{1}^{2}{\frac{dx}{\sqrt{1+{{x}^{2}}}}}\]and\[{{I}_{2}}=\int_{1}^{2}{\frac{dx}{x}}\] then [Pb. CET 2004]

Let \[{{I}_{1}}=\int_{1}^{2}{\frac{dx}{\sqrt{1+{{x}^{2}}}}}\]and\[{{I}

1.	Let \[{{I}_{1}}=\int_{1}^{2}{\frac{dx}{\sqrt{1+{{x}^{2}}}}}\]and\[{{I}_{2}}=\int_{1}^{2}{\frac{dx}{x}}\] then [Pb. CET 2004]
A.	\[{{I}_{1}}>{{I}_{2}}\]
B.	\[{{I}_{2}}>{{I}_{1}}\]
C.	\[{{I}_{1}}={{I}_{2}}\]
D.	\[{{I}_{1}}>2{{I}_{2}}\]
Answer» C. \[{{I}_{1}}={{I}_{2}}\]

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Let \[{{I}_{1}}=\int_{1}^{2}{\frac{dx}{\sqrt{1+{{x}^{2}}}}}\]and\[{{I}_{2}}=\int_{1}^{2}{\frac{dx}{x}}\] then [Pb. CET 2004]

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