Let \[f(x)=\left\{ \begin{align} & \frac{x-4}{|x-4|}+a,\ x4 \\ \end{align} \right.\]. Then \[f(x)\]is continuous at \[x=4\] when

Let \[f(x)=\left\{ \begin{align} & \frac{x-4}{|x-4|}+a,\ x4 \\ \end

1.	Let \[f(x)=\left\{ \begin{align} & \frac{x-4}{\|x-4\|}+a,\ x4 \\ \end{align} \right.\]. Then \[f(x)\]is continuous at \[x=4\] when
A.	\[a=0,\ b=0\]
B.	\[a=1,\ b=1\]
C.	\[a=-1,\ b=1\]
D.	\[a=1,\ b=-1\]
Answer» E.

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Let \[f(x)=\left\{ \begin{align} & \frac{x-4}{|x-4|}+a,\ x4 \\ \end{align} \right.\]. Then \[f(x)\]is continuous at \[x=4\] when

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