Let \[f(x)=\frac{{{x}^{2}}-4}{{{x}^{2}}+4}\] for \[|x|\ >2\], then the function \[f:(-\infty ,\ -2]\cup [2,\ \infty )\to (-1,\ 1)\] is [Orissa JEE 2002]

Let \[f(x)=\frac{{{x}^{2}}-4}{{{x}^{2}}+4}\] for \[|x|\ >2\], then the

1.	Let \[f(x)=\frac{{{x}^{2}}-4}{{{x}^{2}}+4}\] for \[\|x\|\ >2\], then the function \[f:(-\infty ,\ -2]\cup [2,\ \infty )\to (-1,\ 1)\] is [Orissa JEE 2002]
A.	One-one into
B.	One-one onto
C.	Many one into
D.	Many one onto
Answer» D. Many one onto

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Let \[f(x)=\frac{{{x}^{2}}-4}{{{x}^{2}}+4}\] for \[|x|\ >2\], then the function \[f:(-\infty ,\ -2]\cup [2,\ \infty )\to (-1,\ 1)\] is [Orissa JEE 2002]

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