Let \[f(x)=\frac{x}{1+{{x}^{2}}}\] and \[g(x)=\frac{{{e}^{-x}}}{1+[x],}\], where \[[x]\]is the greatest integer less than or equal to x, then

\[R(f)\cap R(g)=\left[ -2,\frac{1}{2} \right]\]

Let \[f(x)=\frac{x}{1+{{x}^{2}}}\] and \[g(x)=\frac{{{e}^{-x}}}{1+[x],

1.	Let \[f(x)=\frac{x}{1+{{x}^{2}}}\] and \[g(x)=\frac{{{e}^{-x}}}{1+[x],}\], where \[[x]\]is the greatest integer less than or equal to x, then
A.	\[D(f+g)=R-[-2,0)\]
B.	\[D(f+g)=R-[-1,0)\]
C.	\[R(f)\cap R(g)=\left[ -2,\frac{1}{2} \right]\]
D.	None of these
Answer» E.

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Let \[f(x)=\frac{x}{1+{{x}^{2}}}\] and \[g(x)=\frac{{{e}^{-x}}}{1+[x],}\], where \[[x]\]is the greatest integer less than or equal to x, then

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