Let \[f(x)=\frac{{{({{e}^{x}}-1)}^{2}}}{\sin \left( \frac{x}{a} \right)\log \left( 1+\frac{x}{4} \right)}\] for \[x\ne 0,\] and \[f(0)=12\]. If f is continuous at \[x=0\], then the value of a is equal to

Let \[f(x)=\frac{{{({{e}^{x}}-1)}^{2}}}{\sin \left( \frac{x}{a} \right

1.	Let \[f(x)=\frac{{{({{e}^{x}}-1)}^{2}}}{\sin \left( \frac{x}{a} \right)\log \left( 1+\frac{x}{4} \right)}\] for \[x\ne 0,\] and \[f(0)=12\]. If f is continuous at \[x=0\], then the value of a is equal to
A.	1
B.	-1
C.	2
D.	3
Answer» E.

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Let \[f(x)=\frac{{{({{e}^{x}}-1)}^{2}}}{\sin \left( \frac{x}{a} \right)\log \left( 1+\frac{x}{4} \right)}\] for \[x\ne 0,\] and \[f(0)=12\]. If f is continuous at \[x=0\], then the value of a is equal to

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