Let \[f(x)=\frac{\alpha {{x}^{2}}}{x+1},x\ne -1.\] The value of \[\alpha \] for which \[f(a)=a,(a\ne 0)\] is

Let \[f(x)=\frac{\alpha {{x}^{2}}}{x+1},x\ne -1.\] The value of \[\alp

1.	Let \[f(x)=\frac{\alpha {{x}^{2}}}{x+1},x\ne -1.\] The value of \[\alpha \] for which \[f(a)=a,(a\ne 0)\] is
A.	\[1-\frac{1}{a}\]
B.	\[\frac{1}{a}\]
C.	\[1+\frac{1}{a}\]
D.	\[\frac{1}{a}-1\]
Answer» D. \[\frac{1}{a}-1\]

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Let \[f(x)=\frac{\alpha {{x}^{2}}}{x+1},x\ne -1.\] The value of \[\alpha \] for which \[f(a)=a,(a\ne 0)\] is

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