Let \[f(x)\]and \[g(x)\]be two functions having finite non-zero 3rd order derivatives \[{f}'''(x)\]and \[{g}'''(x)\] for all, \[x\in R\]. If \[f(x)g(x)=1\]for all \[x\in R\], then \[\frac{{{f}'''}}{{{f}'}}-\frac{{{g}'''}}{{{g}'}}\]is equal to

\[3\text{ }\left( \frac{g''}{g}-\frac{f''}{g} \right)\]

\[3\text{ }\left( \frac{{{f}''}}{g}-\frac{{{g}''}}{f} \right)\]

\[3\text{ }\left( \frac{{{f}''}}{f}-\frac{{{g}''}}{g} \right)\]

\[3\text{ }\left( \frac{{{f}''}}{f}-\frac{{{g}''}}{f} \right)\]

Let \[f(x)\]and \[g(x)\]be two functions having finite non-zero 3rd or

1.	Let \[f(x)\]and \[g(x)\]be two functions having finite non-zero 3rd order derivatives \[{f}'''(x)\]and \[{g}'''(x)\] for all, \[x\in R\]. If \[f(x)g(x)=1\]for all \[x\in R\], then \[\frac{{{f}'''}}{{{f}'}}-\frac{{{g}'''}}{{{g}'}}\]is equal to
A.	\[3\text{ }\left( \frac{{{f}''}}{g}-\frac{{{g}''}}{f} \right)\]
B.	\[3\text{ }\left( \frac{{{f}''}}{f}-\frac{{{g}''}}{g} \right)\]
C.	\[3\text{ }\left( \frac{g''}{g}-\frac{f''}{g} \right)\]
D.	\[3\text{ }\left( \frac{{{f}''}}{f}-\frac{{{g}''}}{f} \right)\]
Answer» C. \[3\text{ }\left( \frac{g''}{g}-\frac{f''}{g} \right)\]

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Let \[f(x)\]and \[g(x)\]be two functions having finite non-zero 3rd order derivatives \[{f}'''(x)\]and \[{g}'''(x)\] for all, \[x\in R\]. If \[f(x)g(x)=1\]for all \[x\in R\], then \[\frac{{{f}'''}}{{{f}'}}-\frac{{{g}'''}}{{{g}'}}\]is equal to

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