Let \[f:R\to R\] is differentiable function and \[f(1)=4,\] then the value of \[\underset{x\to 1}{\mathop{\lim }}\,\int\limits_{0}^{f(x)}{\frac{2tdt}{x-1}}\] is

Let \[f:R\to R\] is differentiable function and \[f(1)=4,\] then the v

1.	Let \[f:R\to R\] is differentiable function and \[f(1)=4,\] then the value of \[\underset{x\to 1}{\mathop{\lim }}\,\int\limits_{0}^{f(x)}{\frac{2tdt}{x-1}}\] is
A.	\[8f'(1)\]
B.	\[4f'(1)\]
C.	\[2f'(1)\]
D.	\[f'(1)\]
Answer» B. \[4f'(1)\]

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Let \[f:R\to R\] is differentiable function and \[f(1)=4,\] then the value of \[\underset{x\to 1}{\mathop{\lim }}\,\int\limits_{0}^{f(x)}{\frac{2tdt}{x-1}}\] is

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