Let \[f:N\to N\] defined by \[f(x)={{x}^{2}}+x+1\], \[x\in N\], then f is [AMU 2000]

Let \[f:N\to N\] defined by \[f(x)={{x}^{2}}+x+1\], \[x\in N\], then f

1.	Let \[f:N\to N\] defined by \[f(x)={{x}^{2}}+x+1\], \[x\in N\], then f is [AMU 2000]
A.	One-one onto
B.	Many one onto
C.	One-one but not onto
D.	None of these
Answer» B. Many one onto

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Let \[f:N\to N\] defined by \[f(x)={{x}^{2}}+x+1\], \[x\in N\], then f is [AMU 2000]

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