Let f be a differentiable function such that \({f'}\left( x \right) = 7 - \frac{3}{4}\frac{{f\left( x \right)}}{x}\), (x > 0) and f(1) ≠ 4. Then \(\mathop {{\rm{lim}}}\limits_{x \to {0^ + }} xf\left( {\frac{1}{x}} \right)\):

Exists and equals \(\frac{4}{{7}}\).

Let f be a differentiable function such that \({f'}\left( x \right) =

1.	Let f be a differentiable function such that \({f'}\left( x \right) = 7 - \frac{3}{4}\frac{{f\left( x \right)}}{x}\), (x > 0) and f(1) ≠ 4. Then \(\mathop {{\rm{lim}}}\limits_{x \to {0^ + }} xf\left( {\frac{1}{x}} \right)\):
A.	Exists and equals \(\frac{4}{{7}}\).
B.	Exists and equals 4.
C.	Does not exist.
D.	Exists and equals 0.
Answer» C. Does not exist.

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Let f be a differentiable function such that \({f'}\left( x \right) = 7 - \frac{3}{4}\frac{{f\left( x \right)}}{x}\), (x > 0) and f(1) ≠ 4. Then \(\mathop {{\rm{lim}}}\limits_{x \to {0^ + }} xf\left( {\frac{1}{x}} \right)\):

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